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1 year ago

Find the solution of the system of equations.

Mathematics

1 answer:

Alexandra [31]1 year ago

5 0

Answer:

x = -3

y = 9

Step-by-step explanation:

Add two equations up

4x + 5y - 9x - 5y = 33 - 18 add or subtract like terms

-5x = 15 divide both sides by -5

x = -3 we can use this information to find the value of y

4x + 5y = 33 replace x with -3

4 * (-3) + 5y = 33

-12 + 5y = 33 add 12 to both sides

5y = 45 divide both sides by 5

y = 9

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Any help would be greatly appreciated!

Aleks [24]

Answer:

the answer for that question is sqrt(49)

7 0

2 years ago

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Jimmy is selling used books at a yard sale. A customer buys 9 books at a cost of $0.75 each and pays with a $20.00 bill. Jimmy m

never [62]

C= 20-0.75x
c= 20-0.75(9)
c= 20-6.75
c= 13.25

Here c is the amount of change and x is the number of books bought.

The customer's change will be $13.25

3 0

2 years ago

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A can holds 4 golf balls. The diameter of each golf ball is 5 cm. What is the volume of the empty space inside the can?

forsale [732]

Answer:

Volume of the empty space in the can is 327.05 $cm^3$

Step-by-step explanation:

Given:

Number of golf ball the can holds = 4

Diameter of the golf ball = 5 cm

To Find:

Volume of the empty space in the can = ?

Solution:

Step 1: Finding the volume of one golf ball

Ball is shape of the sphere

So lets use the volume of the sphere formula

Volume of the golf ball = $\frac{4}{3}\pi r^3$

Radius = $\frac{5}{2}$ = 2.5 cm

Substituting the values

Volume of the golf ball

= $\frac{4}{3} \pi \times(2.5)^3$

= $\frac{4}{3} \pi \times (15.625)$

= $\frac{4}{3} \times 49.06$

= $\frac{196.24}{3}$

= 65.41

Step 2: Finding the volume of empty space of the can

volume of empty space of the can = volume of 5 golf ball

= 5 X 65.41

= 327.05

7 0

3 years ago

Can someone help out with #3? I'll give Brainliest answer.

quester [9]

The answer is 4√6 4√x
Sorry if that looks confusing but it means small 4, big 6 and then small 4

7 0

2 years ago

An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in

Nikitich [7]

Answer: $4.37\times10^3$

Step-by-step explanation:

Given : Number of choices for novels = 4

Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

Remaining choices for books = 20-4=16

Number of combinations of n things taking r at a time : $\dfrac{n!}{r!(n-r)!}$

Then, the number of different reading schedules are possible :_

$^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3$

Hence, the required answer is $4.37\times10^3$ .

8 0

2 years ago