Answer : The molal freezing point depression constant of X is
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of X liquid (solvent) = 450.0 g
Molar mass of urea = 60 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution =
= freezing point of liquid X=
i = Van't Hoff factor = 1 (for non-electrolyte)
= molal freezing point depression constant of X = ?
m = molality
Now put all the given values in this formula, we get
Therefore, the molal freezing point depression constant of X is
Answer:
Carbon dioxide is a linear covalent molecule.
Carbon dioxide is an acidic oxide and reacts with water to give carbonic acid.
CO 2 + H2O ==> H2CO3
Carbon dioxide reacts with alkalis to give carbonates and bicarbonates.
CO 2 + NaOH ==> NaHCO3 (Sodium BiCarbonate )
NaHCO3 + NaOH ==> Na2CO3 (Sodium Carbonate) + H2O
Answer:
p3=0.36atm (partial pressure of NOCl)
Explanation:
2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) Kp = 51
lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively
p1=0.125atm;
p2=0.165atm;
p3=?
Kp=51;
On solving;
p3=0.36atm (partial pressure of NOCl)