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2 years ago

What is an exponent that has a value between 0 and 1?

1 answer:

6 0

Choose any number such that :

0 < x <1 (it's certainly a decimal number, ex: 0.8; 03; 0.458; 0.9587; etc.

y = aˣ ( a≠ 1 ; a≠ 0 and 0<x<1)

Example: y = aˣ ( assume a = 2 and x = 0.8) → y = 2⁰.⁸ = 1.741101

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Two cars left at the same time. One car travels at an average of 7 miles per hour faster than the other one. First car got their

Elena L [17]

Answer:

s=50.999 and you can round it to s=50.1

Step-by-step explanation:

8 0

2 years ago

Joshua and his children went into a bakery and he bought $15 worth of donuts and cookies. Each donut costs $1.75 and each cookie

Natalija [7]

Answer:

Joshua bought 12 cookies & ABOUT 7 donuts.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

2 years ago

The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.

Arisa [49]

a= 9

b= 19

hope this helps

8 0

2 years ago

Need help asap with work

Dominik [7]

Answer:

f(n)=2+4n

Step-by-step explanation:

when they are combined, there are two taken away, so we can just say that there are two added in total, and the number of grey hexagons is n, and it would be 4n because there are 2 taken away like i said earlier if that makes sense :)

6 0

2 years ago