1 year ago

I need help on understanding what im supposed to do to figure this out.

Mathematics

1 answer:

Sphinxa [80]1 year ago

8 0

Answer:

Correctly given:

$\sqrt{55} < \sqrt{111} < \sqrt{222}$

Step-by-step explanation:

Convert to decimal

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2 years ago

Read 2 more answers

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statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
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