All categories

1 year ago

7 Each day from Monday to Friday, Enrico uses a rideshare scooter to

Mathematics

1 answer:

nekit [7.7K]1 year ago

7 0

Answer:

One all-around trip takes 2.6, while to and from work takes 1.3 miles

Step-by-step explanation:

We know that he rides to and from work from Monday to Friday. This is a total of five days, and since he goes to and from work, he does it twice, meaning he has 5 x 2 = 10 trips. These 10 equal trips all sum to 13 miles, so one trip takes 1.3 miles.

You might be interested in

16-2t=3/2t+9 solve for t

In-s [12.5K]

answer: t=2

steps:

16-2t = 3/2t+9

7 = 3/2t + 2t

2 is 4/2

7 = 3/2t + 4/2t

7 = 7/2t

7/2t = 7

(2/7)7/2t=7(2/7)

t=7(2/7)

t=2

7 0

1 year ago

Find the function value. tan 240°

ivanzaharov [21]

Answer:

Step-by-step explanation:

240 has a reference angle of 60 in the third quadrant. The side across from 60 is going to be negative in this quadrant, measuring -√3; the side adjacent to the angle is also negative in this quadrant, measuring -1. The tangent ratio is the side opposite the angle over the side adjacent to the angle, so

tan(240) = √3

7 0

2 years ago

Which store has the lowest price after discount?

DENIUS [597]

Answer: 99 cent store

Step-by-step explanation:

7 0

2 years ago

-2x+6<4 or 7x+1<-13 what is the answer

Juliette [100K]

I guess x<1 and x<-2

7 0

2 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

10 months ago