Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
Answer:
179200000000
Step-by-step explanation:
My recommendation would be to factor..
x² + 4x + 3 = 0 factor the left side into two binomials
(x + 3)(x + 1) = 0 set each of these binomials equal to zero and solve
x + 3 = 0 Implies x = -3
x + 1 = 0 implies x = -1
A + b + c = 72
a = b - 1
c = b + 1
(b - 1) + b + (b + 1) = 72
Simplify
3b = 72
b = 24
a = 24 - 1
a = 23
The price of the small pots is $2.40 so you would have 2.4s ( multiply the number of small pots by the price)
She bought a total of 14 pots, so the number of large pots would be 14 - s ( subtract the number of small pots from the total )
Now you have:
L = 14-s
2.4s + 5.6(14-s) = 49.6
The answer is C.