Match the graph to one of the following functions.

Stress at work: In a poll conducted by the General Social Survey, 80% of respondents said that their jobs were sometimes or alwa

Svet_ta [14]

Answer:

a) P=0.019

b) P=0.263

c) P=0.794

Step-by-step explanation:

We assume that the poll gives the population's proportion of respondents said that their jobs were sometimes or always stressful (p=0.8).

Then, a sample of size n=190 is taken.

The sample mean is:

$\mu=np=190*0.8=152$

The sample standard deviation is:

$\sigma=\sqrt{np(1-p)}=\sqrt{190*0.8*0.2}=\sqrt{30.4}=5.514$

The probability that 140 or fewer workers find their jobs stressful is:

$z=(X-\mu)/\sigma=(140.5-152)/5.514=-11.5/5.514=-2.08 \\\\P(X\leq140)=P(X$

Note: a correction for continuity is applied.

The probability that more than 155 workers find their jobs stressful is

$z=(X-\mu)/\sigma=(155.5-152)/5.514=3.5/5.514= 0.635 \\\\P(X>155)=P(X>155.5)=P(z>0.635)=0.263$

The probability that the number of workers who find their jobs stressful is between 145 and 158 inclusive is:

$z_1=(X_1-\mu)/\sigma=(158.5-152)/5.514=6.5/5.514= 1.179\\\\ z_2=(X_2-\mu)/\sigma=(144.5-152)/5.514=-7.5/5.514= -1.360 \\\\ P(145\leq X\leq 158)=P(144.5< X< 158.5)\\\\P(145\leq X\leq 158)=P(X$

5 0

2 years ago

Read 2 more answers

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

zepelin [54]

Answer:

If the task is performed in less than or equal to 130.8 seconds, then, the individuals qualify for advanced training.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 150 sec

Standard Deviation, σ = 15 sec

We are given that the distribution of time taken is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.10

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 150}{15})=0.10$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 150}{15} = -1.282\\x = 130.8$

Thus, if the task is performed in less than or equal to 130.8 seconds, then, the individuals qualify for advanced training.

8 0

2 years ago

Blake measures the lengths, in inches, of 10 insects. He records the lengths of the insects on this line plot. He adds the lengt

ivanzaharov [21]

Answer: 5 inches

Step-by-step explanation:

The x's denote the insects measured so the longest insects would be of lengths:

1³/₄ inch, 1³/₄ inch and 1¹/₂ inch.

Adding them together would require converting them to improper fractions first:

7/4, 7/4, 3/2

Pick a denominator that is both denominators' lowest common multiple = 4

Adding them:

Divide the LCM by the denominator of the fraction and multiply the result by the numerator:

= (7 + 7 + 6) / 4

= 20/4

= 5 inches

7 0

2 years ago

I would like to know what 0.5-0.125q=(q-1)/4 equals out to.

Scrat [10]

Answer:

q = 2

Step-by-step explanation:

0.5-0.125q=(q-1)/4

At first, we have to multiply both the sides by 4.

4 × (0.5 - 0.125q) = q - 1

or, 2 - 0.5q = q - 1

now, we change the side by taking constant into the right side and the number into the left side.

2 + 1 = q + 0.5q

or, 3 = q (1 + 0.5)

or, 3 = 1.5 q

or, 1.5 q = 3

or, $\frac{1.5q}{1.5}$ = (3 ÷ 1.5) [Dividing both the sides by 1.5]

or, q = 2

Therefore, q = 2

8 0

2 years ago

ONLY ANSWER IF YOU KNOW IT PLS ILL GIVE THE CORRECT BRAINLIEST!

Bas_tet [7]

Answer:

y=5

Step-by-step explanation

just sub in for x

Y=10-5

7 0

2 years ago