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1 year ago

Solve for x when 4x+16/12=x-4

Mathematics

1 answer:

stira [4]1 year ago

8 0

Answer:

In short, Your Answer would be either 1 or 7

Step-by-step explanation:

|4x + 12| = 16

As it is in modulus function, it could be either +ve or -ve

4x+12 = 16 OR 4x - 12 = 16

4x = 16-12 OR 4x = 16 + 12

4x = 4 OR 4x = 28

x = 4/4 OR x = 28/4

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What is the value of this expression? 6 (24÷ 3) - 2

Makovka662 [10]

Answer:

6 (24÷3) -2

6 (8) -2

48-2

=46

Brackets of division multiplication add and subtract

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2 years ago

The stock market dropped 220 points on Monday. It lost another 48 points on Tuesday, and on Wednesday, it gained 96 points. What

Leona [35]

Answer: 48 points gained in those 3 days.

Subtract 220 with 48, then add 96. Last step would be subtracting 220 with the amount they have now in those 3 days to find how much points the stock market gained in those 3 days.

Subtract 220-48.It‘ll be 172.

Add 172 with 96. 172+96=268.

Subtract 268 with how much points the stock market had 3 days ago. 268-220. So it would be about 48 points gained.

7 0

2 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

2 years ago

How do I solve this problem that’s asking me to find the slope- intercept with two given points: (-9,-14) and (3,2)? I’ve alread

Wittaler [7]

Answer:

4/3 i think

Step-by-step explanation:

(2+14)/(3+9)

7 0

2 years ago

Find the measure of MNI. please help! i’ll give you brainlist!

Sonbull [250]

Answer:

$m\angle MNI = 135^{\circ}$

Step by step explanation:

$\text{The exterior angle of a triangle = sum of two opposite interior angles.}$

$~~~~~~\angle MNI = \angle LMN + \angle MLN\\\\\implies 19x+2=(15x-12)+6x\\\\\implies 19x +2 = 21x-12\\\\\implies 21x -19x = 12+2\\\\\implies 2x = 14\\\\\implies x=\dfrac {14}2\\\\\implies x = 7\\\\\text{So,}~ m\angle MNI = 19(7)+2=135^{\circ}$

5 0

1 year ago

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