Average speed for the entire trip, both ways, is
(Total distance) divided by (total time) .
We don't know the distance from his house to the gift store,
and we don't know how long it took him to get back.
We'll need to calculate these.
-- On the trip TO the store, it took him 50 minutes, at 6 mph.
-- 50 minutes is 5/6 of an hour.
-- Traveling at 6 mph for 5/6 of an hour, he covered 5 miles.
-- The gift store is 5 miles from his house.
-- The total trip both ways was 10 miles.
-- On the way BACK home from the store, he moved at 12 mph.
-- Going 5 miles at 12 mph, it takes (5/12 hour) = 25 minutes.
Now we have everything we need.
Distance:
Going: 5 miles
Returning: 5 miles
Total 10 miles
Time:
Going: 50 minutes
Returning: 25 minutes
Total: 75 minutes = 1.25 hours
Average speed for the whole trip =
(total distance) / (total time)
= (10 miles) / (1.25 hours)
= (10 / 1.25) miles/hours
= 8 miles per hour
A=(1/2)(h)(B+b)
(6)=(1/2)(h)((2)+(1))
12=h(3)
h=4
Answer: h=4
Answer:
(5-2a+6b)/2
Step-by-step explanation:
According to PEMDAS, we would multiply 2 by (a+3b) first. This would equal 2a+6b. Since this is being subtracted from 5, the numerator would equal 5-2a+6b. This would bring the simplified answer to (5-2a+6b)/2
Answer:
Step-by-step explanation:
x+ 8/4 -x+ 5/4
= x+2+-x +5/4
Combine Like Terms:
x+2+-x+ 5/4
(x+x)+ ( 2 +5/4)
= 13/4
A-the data set is symmetrical
