All categories

2 years ago

How many molecules are in 23.47 grams of CO2?

1 answer:

8 0

Do a quick conversion: 1 grams Co2 = 0.0084841820909097 mole using the molecular weight calculator and the molar mass of Co2.

You might be interested in

4.2g of cerium reacted with oxygen to form 5.16g of an oxide of cerium. Find

olganol [36]

Answer:

CeO₂

Explanation:

Hello!

In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:

$n_{Ce}=4.2gCe*\frac{1molCe}{140.12gCe}=0.03molCe\\$

$m_O=5.16g-4.2g=0.96gO\\\\n_O=0.96g*\frac{1molO}{16.0gO} =0.06molO$

Now, we simply divide each moles by 0.03 as the fewest moles in the formula to obtain the simplest formula (empirical formula) of this oxide:

$Ce=\frac{0.03}{0.03}=1\\\\O =\frac{0.06}{0.03}=2$

Thus, the formula turns out:

$CeO_2$

Regards!

6 0

2 years ago

PLEASE HELP this is physical science.

Andru [333]

Bone age : 22,920 years

<h3>Further explanation</h3>

Given

Nt = 2.5 g C-14

No = 40 g

half-life = 5730 years

Required

time of decay

Solution

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

t = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Input the value :

$\tt 2.5=40.\dfrac{1}{2}^{t/5730}\\\\\dfrac{2.5}{40}=\dfrac{1}{2}^{t/5730}\\\\(\dfrac{1}{2})^4=\dfrac{1}{2}^{t/5730}\\\\4=t/5730\rightarrow t=22920~years$

6 0

2 years ago

In the previous problem, which are the limiting reactants for each reaction? Based on this, calculate the maximum yield of oxyge

juin [17]

please show the previous problem

4 0

2 years ago

you find that 7.36g of a compound has decomposed to give 6.93g of oxygen. the only other element in the compound is hydrogen. if

slavikrds [6]

First solve the moles of oxgen present in the compound

mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H

then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
H2O2

8 0

2 years ago

Read 2 more answers

A balloon is filled to a volume of 1.50 L with 3.00 mol of gas at 25 C. with pressure and temperature held constant, what will b

bixtya [17]

Answer:

3.2L

Explanation:

PV=nRT

since pressure and temperature are held constant we have V=nR

R is a constant also,

Thus; $\frac{v1}{n1}=\frac{v2}{n2}$