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1 year ago

HELP PLz i need dis for a grade

Mathematics

2 answers:

labwork [276]1 year ago

4 0

Answer:

99 IQR . its the last one.

Step-by-step explanation:

Tanzania [10]1 year ago

3 0

IQR is 99 so the last one

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There are a total of 66 students in the

attashe74 [19]

Answer:

A = 26

Step-by-step explanation:

sum of students = classA + classB + classC

let's say classA = A, classB = B, and classC = C

A + B + C = 66

class A has five more students than class B, so A = 5 more than B so A = 5+B

class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2

A + B + C = 66

A = 5+B

C = B-2

substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)

(5+B) + B + (B-2) = 66

3B + 3 = 66

subtract 3 from both sides to isolate the variable and its coefficient

3B = 63

divide both sides by 3 to solve for B
B = 21

A = 5 + B = 5 + 21 = 26

7 0

1 year ago

Semester 1 finals are this week for me. Any advice?

krek1111 [17]

Study hard and take the test slowly. rushing will make you get all the wuestions wrong. if you need more advice, message me.

7 0

2 years ago

Read 2 more answers

Information on a packet of seeds, which may not be a random sample of seeds, claims that the germination rate is 94%. What's

Evgesh-ka [11]

Answer:

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p = $\sqrt{\frac{pq}{n} } \\=0.016$

The probability that more than 96% of the 220 seeds in the packet will germinate

= $P(p\geq 0.96)\\=P(Z\geq \frac{0.96-0.94}{0.016})\\=P(Z\geq 1.25)\\==1-0.8948\\=0.1052$

Assumptions are np and nq >5 and also sample size >220 hence normal

7 0

2 years ago

How do u divide fractions

8090 [49]

For example 5/10\1/2 you would keep the 5/10 and flip the 1/2 to 2/1 and then multiply 5\10x2/1 to get 10/10 so 1

8 0

2 years ago

The yearly expenses for the Glenn family are represented in the circle graph. The Glenn’s have just purchased a new car. A new c

tiny-mole [99]

Answer:

Car: 18.4% Other: 4.9%

Step-by-step explanation:

Glenn family yearly total expenses are

$\$8,600+\$4,800+\$5,400+\$2,400+\$7,000+\$1,800=\$30,000$

Other expenses are $7,000.

The payments for the new car are: $375.00 per month and the insurance for the new car $85.00 per month, in total, $460 per month. Yearly expenses for car are

$\$460\cdot 12=\$5,520$

Now, the expenses for the following two categories are

Car - $5,520

Other - $7,000 - $5,520 = $1,480

Percentage:

Car:

$\dfrac{5,520}{30,000}\cdot 100\%=18.4\%$

Other

$\dfrac{1,480}{30,000}\cdot 100\%\approx 4.93\%$

4 0

2 years ago