1885.5 m^3 of water will fill the container.
To find how many cubic feet of water will it contain:
Given -
- Lauren has an above-ground swimming pool.
- The water level in the pool must be 4 inches above the pool's surface in order for the skimmer to function properly.
- π = 3.14
The pool comprises a 12-foot-radius cylinder with a height of 4.5 feet.
- Height of pool = 4.5 ft
- Radius of pool = 12 ft
- The height of the water is 4 inches below the pool top
- 12 inches make 1 ft
- 4 inches = 4/12 ft = 0.33 ft
- Therefore, height of water = 4.5 - 0.33 = 4.17 ft
The volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed.
- The volume of the cylinder formed by the water = volume of water =
- volume = 3.14 x x 4.17 = 1885.5 m^3 of water
Therefore, 1885.5 m^3 of water will fill the container.
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The complete question is given below:
Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14
A cylinder with a radius of 12 feet and a height of 4.5 feet.
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
The answer is that (It’s 6.6)
Answer:2(x+1/2x)+3=105
Step-by-step explanation: that is how i got my answer. If not a similar answer i would go with 2x+3=3x+105.
You can automatically eliminate the first answer. The second one has a random 5, so eliminated. and the last one just isn't correct.
1/10 = .1, and 3/33 = .0909090... it is equivalent if you estimate.