Explanation:
A star is in equilibrium when the pressures inside the star balance out the force of gravity. The pressure is thermal pressure resulting from the fusion reactions taking place in the star's core. A star stays in equilibrium until the supply of hydrogen in the core is depleted.
In a stable star, the gas pressure pushing out from the center is equal with the gravity pulling atoms inward to the center – when these forces are equal, the star is at equilibrium. Once a star reaches equilibrium for the first time, it will start burning (fusing) hydrogen into helium.
Answer: a) 7,00 centimeters
(b) 259. 19 feet
(c) 3110.28 inches
(d) 0.049 miles
Explanation:
(a) We know that 1 meter = 100 centimeters
Therefore,
(b)Since 1 meter = 3.28084 feet
Then,
(c) Since, 1 feet = 12 inches.
(d)
Answer:Electromagnetic force, like all forces, is measured in Newtons. Electrostatic forces are described by Coulomb’s law, and both electric and magnetic forces are covered by the Lorentz force law. However, Maxwell’s four equations provide the most detailed description of electromagnetism.
Explanation:
The change in the kinetic energy refers to the work done in displacing a body, thus, the change in the kinetic energy of an object refers to the work done on the object.
The correct formula to use is:
W = Initial kinetic energy - Final kinetic energy;
Where, W = change in kinetic energy
Final kinetic energy and initial kinetic energy = 1/2 MV^2
Initial velocity = 15 m/s
Final velocity = 13.5 m/s
Initial mass = 0.650 kg
Final mass = 0.950 kg
W = 1/2 [0.650* (15 *15)] - 1/2 [0.950 * (13.5 * 13.5)]
W = 146.25 - 173.13 = 26.88
Therefore, the change in kinetic energy is 26.88 J.
The negative sign has to be ignored, because change in kinetic energy can not be negative.
<span />
Answer:
Explanation:
Given
Time taken to reach ground is
Malda initial velocity
Let h be the height of Cliff
using
where, u=initial velocity
t=time
In first case chirpy drop downward thus u=0
For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]
time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by