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1 year ago

Will mark brainly!! :)

Mathematics

1 answer:

spayn [35]1 year ago

6 0

Answer:

${f}^{ - 1} (x) = - \frac{1}{2} x + \frac{7}{2}$

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What is this simplified? 6-2(3x+1)+4x-5

Olenka [21]

Answer:

-2x - 1

Step-by-step explanation:

6 - 6x - 2 + 4x - 5

6 - 2x - 2 - 5

-2x - 1

8 0

2 years ago

How would I do part A. I showed my work but I'm slightly off

ahrayia [7]

$\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill$

5 0

2 years ago

PLEASE CHOSE THE RIGHT ANSWER AND EXPLAIN WHY YOU CHOSE IT PLEASE

Nikitich [7]

Answer:

Step-by-step explanation:

See attached image.

7 0

1 year ago

Solve for x A 130 B 120 C 23 D 70

34kurt

Answer:

B)120º

Step-by-step explanation:

70+50=x

120=x

7 0

1 year ago

Eight times a sum of a number is 5

nata0808 [166]

Answer:

Step-by-step explanation:

So 8 times what is 5?

8 times x=5

x=0.625

4 0

2 years ago