Answer:
k = 10
Explanation:
The initial polynomial is:
If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:
Therefore, we can solve for k as follows:
So, the value of k is 10
f(9) is the x value, find where the line is in the y direction at x = 9
The line crosses y = 3 at x = 9
Answer:
f(9) = 3
When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.
In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be
or, in interval notation,
In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.
This means that the difference between your numbers at 1 must be at most 4, which is modelled by
where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.
Answer:
C) 16, 6
Step-by-step explanation:
- Set AB and DC equal to eachother. 4x = x + 12.
- Subtract x from both sides. 3x = 12
- Divide by 3 to get x alone. x = 4
- Plug this x value in the equation for AB. 4•(4) = 16
- We know the AD equals 6, so that will be one of the values and we now know that AB equals 16.
Answer:
In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.