Answer:
The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules
Explanation:
The given spring constant of the of the spring, k = 88.0 N/m
The length by which the hose is stretched, x = 4.20 m
For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose
The elastic potential energy, P.E., of a compressed spring is given as follows;
P.E. = 1/2·k·x²
∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²
1/2 × 88.0 N/m × (4.20 m)² = 776.16 J
The work done on the hose = The potential energy given to hose, P.E. = 776.16 J
<span>The correct option is A, that is, non-verbal communication. Non-verbal communication is defined as the kind of communication that are passed across without using words. Examples of this are: shaking of hands, hugging, back-patting, facial expression, eye-contact and every form of communication that are make use of without the usage of words.</span>
Answer:
The speed of the wave with a frequency 100 mhz will be
Explanation:
We have given that frequency of light is 100 mhz
We have to find the speed of light in vaccuum
We know that all electromagnetic waves travels in vaccum wth the same speed as the speed of light
And we know that speed of light is equal to
So the speed of the wave with a frequency 100 mhz will be
It often requires STANDARD reaction time