Answer:
A=2(wl+hl+hw)
Step-by-step explanation:
Simplify the expression:
8(2x - 3) - 6x = 8×2x - 8×3 - 6x = 16x - 24 - 6x = 10x - 24
for x=3
put value of "x" to the expression:
<u>10×3 - 24 = 30 - 24 = 6</u>
Three-forty one over one thousand XD
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation .
In this problem:
- The mean is of 660, hence .
- The standard deviation is of 90, hence .
- A sample of 100 is taken, hence .
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:
By the Central Limit Theorem
has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
20,24,28
Step-by-step explanation: