If f(x) = 5x2 + 3, find f(-2) =
1 answer:
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Given:
The function is
To find:
The range value if the domain value is 1.75.
Solution:
Domain is the set of input values and range is the set of output values.
Here, range value if the domain value is 1.75. It means the value of function f(x) at x=1.75.
Substitute x=1.75 in the given function.
Therefore, the required range value is 4.5.
We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer
<span>considering the case N 2 </span>is
vertex (4,-1)------> is correct
y intercept (0,-17)-----> is correct
axis of symmetry x=4-----> is correct
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer
<span>considering the case N 2 </span>is
vertex (4,-1)------> is correct
y intercept (0,-17)-----> is correct
axis of symmetry x=4-----> is correct