Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
Because the cells can only use energy in form of ATP.
Its like you can't run a diesel truck on petrol.
Answer: Option B) phosphate; hydroxyl; 3'
We identify nucleic acid strand orientation on the basis of important chemical functional groups. These are the phosphate group attached to the 5' carbon atom of the sugar portion of a nucleotide and the hydroxyl group attached to the 3'
carbon atom
Explanation:
For both RNA and DNA, chemical groups such as phosphate (PO3-) attaches to the 5' carbon of the pentose sugar (deoxyribose in DNA, ribose in RNA).
While hydroxyl group (OH) attaches to the 3' carbon atom of the pentose sugar.
Thus, a nucleic acid structure structure reveals a several repeating units of nucleotides where nitrogenous base links to a pentose sugar, who in turns is linked to phosphate group
Answer:
Warm front
Explanation:
A warm front is the transition zone of the replacement of a cold air mass by a warm air mass. The pressure centers of warm fronts are usually low and the pressure read by a barometer will decrease due to an incoming warm front
The general direction of motion of warm fronts is from southwest to northeast with warmer and moist air behind the warm front than air into which the front flows. Therefore, warm fronts normally results in moderate precipitation or rainfall or snow.
