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2 years ago

2MG+O2 ...........2MGO

1 answer:

5 0

Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced

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Determine the molar mass of a gas that moves 1.25 times as fast as CO2.

Lerok [7]

The molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

<h3>Molar mass of the gas</h3>

The molar mass of the gas is determined by applying Graham's law of diffusion.

R₁√M₁ = R₂√M₂

R₁/R₂ = √M₂/√M₁

R₁/R₂ = √(M₂/M₁)

where;

R₁ is rate of the CO2 gas
M₁ is molar mass of CO2 gas
R₂ is rate of the second gas
M₂ is the molar mass of the second gas

R₁/1.25R₁ = √(M₂/44)

1/1.25 = √(M₂/44)

0.8 = √(M₂/44)

0.8² = M₂/44

M₂ = 0.8² x 44

M₂ = 28.16 g

Thus, the molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

Learn more about molar mass here: brainly.com/question/21334167

#SPJ1

3 0

1 year ago

For many purposes we can treat propane (CH) as an ideal gas at temperatures above its boiling point of - 42°C. Suppose the tempe

fredd [130]

Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.58 kPa

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = v

$V_2$ = final volume of gas = $v-\frac{40}{100}\times v=0.6v$

$T_1$ = initial temperature of gas = $25^0C=(25+273)K=298K$

$T_2$ = final temperature of gas = $-22^0C=(-22+273)K=251K$

Now put all the given values in the above equation, we get:

$\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}$

$P_2=0.81kPa$

The final pressure is 0.81 kPa

3 0

2 years ago

What are all of the elements that end with F electrons

jonny [76]

The elements whose electron configurations end with f electrons are in the Lanthanide and Actinide series: those long series at the bottom of the Periodic Table (see image).

The atoms are adding electrons into f orbitals, but the f electrons are not always the last electrons in the electron configuration.

For example, the electron configuration of Eu is [Xe]6s²4f⁷, but that of Gd

is [Xe] 6s²4f⁷5d.

I have blocked off in <em>red</em> all the <em>exceptions</em> like Gd.

5 0

2 years ago

How many miles are in 68 grams of copper 2 hydroxide, Cu (OH)2

BabaBlast [244]

Molar mass Cu(OH)₂ = <span>97.561 g/mol

1 mol --------- 97.561 g
? mol ---------- 68 g

moles = 68 * 1 / 97.561

moles = 68 / 97.561

= 0.6969 moles

hope this helps!</span>

8 0

2 years ago

Compute the following and give your answer on scientific notation

Nata [24]

Answer:

6*10^-3

Hope it helps

Procedure in the attached file

4 0

2 years ago