All categories

1 year ago

If b= 62 degrees and c=24, find b.

Mathematics

2 answers:

DENIUS [597]1 year ago

8 0

Answer A

21.2

Step-by-step explanation:

vekshin11 year ago

3 0

Answer:

21.2

Step-by-step explanation:

b = sin of angle B times length of c

b = 24*sin(62) = 21.1907

You might be interested in

Suppose f(x) = x^2 and

SpyIntel [72]

Given:

The two functions are:

$f(x)=x^2$

$g(x)=\left(\dfrac{1}{3}x\right)^2$

To find:

The statement that best compares the graph of g(x) with the graph of f(x).

Solution:

The horizontal stretch is defined as:

$g(x)=f(kx)$ ...(i)

If $0$ , the function f(x) is horizontally stretched by factor $\dfrac{1}{k}$ .

If $k>1$ , the function f(x) is horizontally compressed by factor $\dfrac{1}{k}$ .

We have,

$f(x)=x^2$

$g(x)=\left(\dfrac{1}{3}x\right)^2$

Using these functions, we get

$g(x)=f\left(\dfrac{1}{3}x\right)$ ...(ii)

On comparing (i) and (ii), we get

$k=\dfrac{1}{3}$

Since $0$ , the function f(x) is horizontally stretched by factor $\dfrac{1}{\frac{1}{3}}=3$ .

Hence, the correct option is D.

5 0

2 years ago

A small box of cereal weighs k grams. A jumbo box of cereal weighs 5 times as much.

mariarad [96]

Answer:

k=m/5

Step-by-step explanation:

explained in the attached pi

3 0

2 years ago

The scores on an exam are normally distributed, with a mean of 74 and a standard deviation of 7. What percent of the scores are

Lynna [10]

A normal distribution with a mean of 74 and a standard deviation of 7.
Mean + 1 SD = 74 + 7 = 81
Less than 81 : 50 % + 34 % = 84 %
Answer:
A ) 84 %

4 0

2 years ago

Read 2 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

F(x) = 4x + 2 ; g(x) = 2x ; find f(g(4)) HELPP PLS

Dennis_Churaev [7]

Answer:

ion know

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers