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1 year ago

82 children visit a sports centre.

Mathematics

1 answer:

igomit [66]1 year ago

3 0

Answer:

4 adults are there to look out for the 12 kids and

and at least 2 adults are there to look out at the dancers

Step-by-step explanation:

hope this helps(^_^") fat guy deluxe (΄◞ิ౪◟ิ‵ )

please mark me brainliest!

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11. Higher Order Thinking Using what you know

Lynna [10]

Answer:

m∠1 + m∠3 = m∠2 + m∠4

Step-by-step explanation:

In the figure attached,

In the given trapezoid if two sides AB and CD are parallel and AD is a transverse,

m∠1 + m∠3 = 180°

Similarly, if AB and CD are parallel and BC is a transverse,

m∠2 + m∠4 = 180°

Therefore, m∠1 + m∠3 = m∠2 + m∠4 is the relation between these angles.

6 0

2 years ago

A student needs to collect exactly 20 insects for a science project. The student has already collected 13 insects. Write an equa

sergeinik [125]

Answer:

The answer is c: N + 13 = 20

Step-by-step explanation:

8 0

3 years ago

there were 64 basketball games during the NCAA tournament 16 of those games were decided by 3 points or less what percentage of

kirill115 [55]

Answer:

25%

Step-by-step explanation:

We can use a proportion to answer this question:

64 represent the 100% of the games

so:

x : 100 = 16 : 64

x = (16*100)/64 = 1600/64 = 25%

7 0

2 years ago

2+2

brilliants [131]

So true that is why haha

5 0

2 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

2 years ago