C distillation you would evaporate the water into another container leaving you with the salt free water
Answer: The final concentration of aluminum cation is 0.335 M.
Explanation:
Given: = 47.8 mL (1 mL = 0.001 L) = 0.0478 L
= 0.321 M, = 21.8 mL = 0.0218 L, = 0.366 M
As concentration of a substance is the moles of solute divided by volume of solution.
Hence, concentration of aluminum cation is calculated as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.
Answer:
2.951 × 10⁻⁵ M
Explanation:
Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.
HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)
Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.
pH = -log [H₃O⁺]
[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M
The melting point for ice is at 32 degrees <span>Fahrenheit or O degrees Celsius.</span>