Answer:
formula
ΔP= PgΔh
Explanation:
Calculation.
ΔP = (1.05 x 10^3kg/m^3)(9.8m/s^2)(6ft equivalent to 1.8288m)
ΔP = 1.05 x 10^3 kg/m^3 x 9.8m/s^2.
x1.8288.
ΔP = 1.88 x 10^4 Pa.
2.37eV stopping potential would be required to arrest the current of photoelectrons.
<h3 /><h3>What is stopping potential ?</h3>
The minimal negative voltage that must be provided to the anode to halt the photocurrent is known as stopping potential. When expressed in electron volts, the maximal kinetic energy of the electrons is equal to the stopping voltage.
Kmax = eV₀
2.37eV = eV₀
V₀ = 2.37eV
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Province. Is what is located away from the capital.
Answer:
t = 1.77 s
Explanation:
The equation of a traveling wave is
y = A sin [2π (x /λ -t /T)]
where A is the oscillation amplitude, λ the wavelength and T the period
the speed of the wave is constant and is given by
v = λ f
Where the frequency and period are related
f = 1 / T
we substitute
v = λ / T
let's develop the initial equation
y = A sin [(2π / λ) x - (2π / T) t +Ф]
where Ф is a phase constant given by the initial conditions
the equation given in the problem is
y = 5.26 sin (1.65 x - 4.64 t + 1.33)
if we compare the terms of the two equations
2π /λ = 1.65
λ = 2π / 1.65
λ = 3.81 m
2π / T = 4.64
T = 2π / 4.64
T = 1.35 s
we seek the speed of the wave
v = 3.81 / 1.35
v = 2.82 m / s
Since this speed is constant, we use the uniformly moving ratios
v = d / t
t = d / v
t = 5 / 2.82
t = 1.77 s