Answer:
x = 0
Step-by-step explanation:
i) x - 11 + 1 < 15
x - 10 < 15
x < 10 + 15
x < 25
ii) x - 11 + 1 > 15
x - 10 > 15
x > 25
Therefore to compare (i) and (ii)
25 < x < 25
In any case, x = 0
Answer:
7x12x2=168 I think but how did u do this
the negative - positive
- 24/-4
24/4
6
Answer:
Step-by-step explanation:
<h3>sorry butt can you tell me what you need help with</h3>
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa