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1 year ago

How are passengers affected when a moving bus is stopped suddenly? Explain with reason.

Physics

1 answer:

Mademuasel [1]1 year ago

5 0

Answer:

When a moving bus stops suddenly, the passenger are pushed forward because of the inertia of the passengers. ... Because the lower part of the body comes to rest with the bus while the upper part tends to continue its motion due to inertia.

Explanation :

The passengers in a bus tend to fall backward when it starts suddenly due to inertia as the passengers tend to remain in the state of rest while the bus starts to move. When the bus stops suddenly, people fall forward because their inertia as they are in state of motion even when the bus has come to rest.

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A convex lens with focal length 9 cm forms an image of an object placed 21 cm to the left of the lens. what is the distance to t

bixtya [17]

Answer:

15.75 cm

Explanation:

focal length of convex lens, f = + 9 cm

position of object, u = - 21 cm

Let the distance of image is v.

Use lens equation

1 / f = 1 / v - 1 / u

1 / 9 = 1 / v + 1 / 21

1 / v = 1 / 9 - 1 / 21 = (21 - 9) / (21 x 9)

1 / v = 12 / 189

v = 15.75 cm

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nika2105 [10]

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2 years ago

A proton, mass 1.67 × 10−27 kg and charge +1.6 × 10−19 c, moves in a circular orbit perpendicular to a uniform magnetic field of

stellarik [79]

Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s

Explanation:

For proton, the centripetal force required for circular motion is provided by the magnetic force,

so Fm= Fc

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m= mass of charged particle

v= velocity

B =magnetic field

q= charge

r= radius of circular path

v= q B r/m

now v= r ω

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ω r = q B r /m

ω=q B /m

now ω= 2π/T where T =time period

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2 years ago

Consider two particles A and B. The angular position of particle A, with constant angular acceleration, depends on time accordin

Vera_Pavlovna [14]

Answer:

θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

Explanation:

This is an angular kinematic exercise the equation for the angular position

the particle A

θ = θ₀ + ω₀ t + ½ α t²

They say for the particle B

w₀B = ½ w₀

αB = 2 α

In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial

t´ = t - t_1

et's write the equation of particle B

θ = θ₀ + w₀B t´ + ½ αB t´2

replace

θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²

θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

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2 years ago

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DedPeter [7]

Answer:

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