All categories

1 year ago

Help please!

Physics

1 answer:

JulsSmile [24]1 year ago

7 0

3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:

(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v

where v is the velocity of the combined players. Solve for v :

450 kg•m/s - 320 kg•m/s = (155 kg) v

v = (130 kg•m/s) / (155 kg)

v ≈ 0.84 m/s

4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that

(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v

where v is the new velocity of the 4-kg ball. Solve for v :

30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v

v = (16.4 kg•m/s) / (4 kg)

v = 4.1 m/s

You might be interested in

A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre

ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined using equation of motion

$S=ut+\frac{1}{2} at^2$

where $u$ is the initial velocity which is zero here

$t$ is time taken, $a$ is acceleration due to gravity

the position of first drop after time $t$ is given by

$S_{1} =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)$

the position of next drop at same time is

$S_{2} =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)$

distance between them is $S_{1} -S_{2}$ is $a(t-1)$

from the above the difference will increase with the time

3 0

2 years ago

A student, standing on a scale in an elevator at rest, sees that his weight is 840 n. as the elevator rises, his weight increase

Firlakuza [10]

<span>1) at rest his weight is 840 N

=> 840N = mass * g => mass = 840 N / g = 840 N / 9.8 m/s^2 = 85.7 kg

2) as the elevator rises, his weight increases to 1050 N,

The reading of the scale is the norma force of it over the body of the person.

And the equation for the force is: Net force = mass * acceleration = normal force - weight at rest

=> mass * acceleration = 1050 N - 840 N = 210 N

acceleration = 210 N / mass = 210 N / 85.7 kg = 2.45 m/s^2 (upward)

3) when the elevator slows to a stop at the 10th floor, his weight drops to 588 N

=> mass * acceleration = 588 N - 840 N = - 252 N

=> acceleration = - 252 N / 85.71 kg = - 2.94 m / s^2 (downward)

Answer:

Acceleration at the beginning of the trip 2.45 m/s^2 upward
Acceleration at the end of the trip 2.94 m/s^2 downward
</span>

6 0

2 years ago

Jason and Guy are throwing watermelons straight up from the ground. (They’re making fruit salad.) Jason throws his watermelon at

NISA [10]

Answer:2t

Explanation:

Given

Jason throwing watermelon at speed v and it spend t time in air

time to reach max height

$v_f=u_i+at'$