How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?.

Mathematics

1 answer:

attashe74 [19]1 year ago

8 0

You can use the change of base formula to get

$\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856$

and also

$\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950$

In general, the change of base formula is

$\log_b(x) = \frac{\log(x)}{\log(b)}$

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Step-by-step explanation:

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Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

$Solve \: for \: a: \\ = > w=3(2a+b)-4 \\ \\ w=3(2a+b)4 \: is \: equivalent \: to \: 3(2a+b)-4= w: \\ = > 3(2a+b) - 4=w \\ \\ Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ = > (3 \times 2a) + (3 \times b) - 4 = w \\ = > 6a+3b - 4=w \\ \\ Subtract \: 3b - 4 \: from \: both \: sides: \\ = > 6a + 3b - 4 - (3b - 4)=w - (3b - 4) \\ = > 6a = w - 3b + 4 \\ \\ Divide \: both \: sides \: by \: 6: \\ = > \frac{ \cancel{6}a}{ \cancel{6}} = \frac{w - 3b + 4}{6} \\ = > a = \frac{w}{6} - \frac{3b}{6} + \frac{4}{6} \\ = > a = \frac{w}{ 6} - \frac{b}{2} + \frac{2}{3}$