Answer:
£1638.40
Step-by-step explanation:
Step one:
Given data
A car costs £5000 when new
Each year the value decreases by 20%.
Step two:
let us compute the worth in the next 5 years
year 1
worth= 5000- 0.2*5000
worth= 5000-1000
worth= £4000
year 2
worth= 4000- 0.2*4000
worth= 4000-800
worth= £3200
year 3
worth= 3200- 0.2*3200
worth= 3200-640
worth= £2560
year 4
worth= 2560- 0.2*2560
worth= 2560-512
worth= £2048
year 5
worth= 2048- 0.2*2048
worth= 2048-409.6
worth= £1638.40
The person is wrong because after 5 years the car is worth £1638.40
Answer:
for the first question, it's (2,2) and for the last question it's (0,2)
ANSWER
EXPLANATION
The given vector is v = −14.5i + 2.5 j.
The magnitude of this vector is
The unit vector in the direction of this vector is
Answer:
Length = 3.84 feets (nearest hundredth)
Step-by-step explanation:
The length of section of wire can be obtyaiejd using the length of of a arc formular :
Length of arc = θ/360° * 2πr
Radius, r = 2.5 feets
Length of arc = (88/360) *2πr
Length of arc = (88/360) * 2π*2.5
Length of arc = 0.244444 * 15.707963
Length of arc = 3.8397
Length = 3.84 feets (nearest hundredth)
Answer:
On the graphing calculator, use the function normCdf, where
- lower bound = -9999
- upper bound = 210
- mean = 250
- standard deviation = 46
It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%