So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
C) YQ = 8
Step-by-step explanation:
If WQ is 8 and XZ bisects this line, this means that YQ is also 8.
If this answer is correct, please make me Brainliest!
Answer:
2.5
Step-by-step explanation:
Answer:
I believe the answer to this question is: (-3,1) X=-3, Y=1.
You have to find what x equals i think
