I saw the complete problem:
complete the exercise below to decompose 930
930 = _____ tens = ____ x ____
My answer is:
930 = ninety-three tens or 93 tens = 93 x 10
Answer:
See the image below:)
Step-by-step explanation:
I can only show half of the steps, but these are some of the steps. You can use the app photo math, just take a picture and it will show you the steps and answer.
Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = - = - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
Would have to be C due to all the other numbers not adding up to be a right angle
Answer: the graph is not shown, but I'll try to explain how hypothetically, you would be able to graph g(10). If you are given something like an image of the graph, find slope and y-intercept first. The y-intercept is the point (0, #), and is on the y-axis. After finding what g(x) = mx + b <- slope intercept form is, substitute 10 for x, then solve.
Step-by-step explanation: