For this case we have the following equation:
d = 0.5 + 5t
We will describe the equation step by step.
0.5: Initial distance Jillian walked
5: speed with which Jillian begins to jog
t: independent variable that indicates the number of hours
y: dependent variable that indicates the distance traveled in miles
Answer:
The variable variable is time and the dependent variable is distance.
Sorry for my messy handwriting but this is the answer
3 is 13 more than 10, and 3 is 30% of 10, so 30% im pretty sure
Answer:
Option: C is the correct answer.
C. Periodic with period 4 and amplitude of about 15.
Step-by-step explanation:
We are given the table of values as:
Hour 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11
Number 24-41-10-32-26-38-9-31-25-39-12
of boats
As we could see that after every 4 value the values are approximately repeating.
Hence,the data set is approximately periodic.
Also, the amplitude is calculated as:
Average of the maximum and minimum value of each set
We divide the set into 3 sets as follows:
Hour 1 2 3 4
Number of boat 24 41 10 32
Here we have amplitude as:
(41-10)/2=15.5
Hour 5 6 7 8
Number of boat 26 38 9 31
Amplitude is:
(38-9)/2=14.5
Hour 9 10 11 12
Number of boat 25 39 12
Amplitude is:
(39-12)/2=13.5
Hence, we see that the amplitude is about 15.
Answer:
Step-by-step explanation:
I haven't got time to do all these by I'll give you the method in each case.
You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.
A . Multiply equation 2 by 2 and subtract (to eliminate x)
- don't forget to multiply EACH TERM by 2.
B. Multiply equation 2 by -2 and add.
C. Multiply equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so you then add to eliminate y.
D. Multiply equation 1 by 13 and equation and equation 2 by 2 to eliminate x then add.
