The fare of $(20 - 2.5) = $17.5 will maximize the total fare.
<h3>What is Differentiation?</h3>
Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.
Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.
It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.
for $x increase in fare, 20x less people will take the trip and at that time the total fare F is given by
f(x) =(20 + x)(500 - 20x)
f (x) = 10000 + 100x - 20x²
For f(x) to be maximum, the condition is dy/dx = 0
100 - 40x = 0
⇒ x = 2.5
Thus, the fare of $(20 - 2.5) = $17.5 will maximize the total fare.
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Answer:
6)C,120
7)B,60°
DOES THE ANSWER HELP YOU?
Answer:
<em>The answer is 1.2001 * 10^-5</em>
<h3>
Answer: 14.85 + c = 20</h3>
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Reason:
To compute the change, we subtract the amount William gives the cashier (the $20) and the price of the book ($14.85)
The change c is
c = 20-14.85
To rearrange this equation, we can add 14.85 to both sides to end up with 14.85 + c = 20
In other words, solving that equation in bold leads to c = 20-14.85 = 5.15 which is the change William is given.
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Extra info (optional section)
If the cashier wanted to mentally figure out the change in his/her head, then notice the jump from 85 cents to 100 cents is 15 cents. That means we go from 14.85 to 15.00
Then the jump from $15 to $20 is an extra 5 dollars. Overall, the total change given back to William is 0.15+5 = 5.15 dollars.
9514 1404 393
Answer:
F20 = 15985k -20361g
Step-by-step explanation:
If we assume F3 and F4 are the third and fourth terms of an arithmetic sequence, the common difference is ...
d = F4 -F3 = (945k -713g) -(5k +515g)
d = 940k -1228g
Then the 20th term is ...
F20 = F3 +(20 -3)d = (5k +515g) +17(940k -1228g)
F20 = 15985k -20361g