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1 year ago

Lesson 3: Revisiting Proportional Relationships

Mathematics

1 answer:

lina2011 [118]1 year ago

8 0

Relationship is going to work out so 72728

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400 m in 32 s - runners speed

Harman [31]

Answer:

12.5 m in 1 second.

Step-by-step explanation:

400/32=12.5

6 0

2 years ago

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Find f(x) and g(x) so that the function can be described as y=f(g(x))<br> y=(9/x^2)+2

eduard

there are many combinations for it, but we can settle for say

$\bf \begin{cases} f(x)=x+2\\[1em] g(x)=\cfrac{9}{x^2}\\[-0.5em] \hrulefill\\ (f\circ g)(x)\implies f(~~g(x)~~) \end{cases}\qquad \qquad f(~~g(x)~~)=[g(x)]+2 \\\\\\ f(~~g(x)~~)=\left[ \cfrac{9}{x^2} \right]+2\implies f(~~g(x)~~)=\cfrac{9}{x^2}+2$

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2 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

2 years ago

Please help me with homework will give brainliest

slavikrds [6]

Answer:

Step-by-step explanation:

We see that there are 3 in step 2 which means that the only possible answer is A

7 0

2 years ago

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Xavier walked 8 miles in 5 hours. What was his walking rate in miles per hour?

inna [77]

Answer:

0.6 miles per hours per hour

Step-by-step explanation:

Simply divide 5 by 8

your answer: 0.6 miles per hour.

7 0

2 years ago