5. Location A is in the center of a large desert. What factor could account for its low annual

1 answer:

4 0

Given what we know about the mechanisms surrounding weather, we can confirm that Large deserts receive less rainfall due to the lack of bodies of water and "rainshadows".

Rainshadow is a term used to describe the effects of nearby mountains on the rainfall amounts of a desert. The mountain causes the air to rise greatly and lose moisture. This moisture is received by the mountain, which means that it does not reach the desert area.

Another limiting factor for the amount of rainfall received by deserts is the lack of bodies of water in the area. Once a desert is formed, it tends to lack large bodies of water. This limits the rainfall it receives given that there is no water nearby to evaporate and cause the formation of clouds.

To learn more visit:

brainly.com/question/1051337?referrer=searchResults

You might be interested in

Which will cause an increase in the reaction rate between molecules?

Mariana [72]

I think it's B. Molecules collide more frequently

3 0

2 years ago

Which material has carbon atoms interspersed with iron atoms in its molecular structure?

gogolik [260]

Answer:

steel should be correct

4 0

2 years ago

Question 1 of 30

Ksivusya [100]

The answer will be A

3 0

2 years ago

Read 2 more answers

Regarding the Lyman series of hydrogen, calculate the frequency of the n = 5 line.

zvonat [6]

The Lyman series can be expressed in the formula 1/λ=RH(1−1/n2) where RH=1.0968×107m−1=13.6eVhc

Where n is a natural number greater than or equal to 2 (i.e. n = 2,3,4,...). Therefore, the lines seen in the image above are the wavelengths corresponding to n=2 on the right, to n=∞on the left (there are infinitely many spectral lines, but they become very dense as they approach to n=∞ (Lyman limit), so only some of the first lines and the last one appear).
The wavelengths (nm) in the Lyman series are all ultraviolet
:2 3 4 5 6 7 8 9 10 11
Wavelength (nm) 121.6 102.6 97.3 95 93.8 93.1 92.6 92.3 92.1 91.9 91.18 (Lyman limit)
In your case for the n=5 line you have to replace "n" in the above formula for 5 and you should get a value of 95 x 10^-9 m for the wavelength. then you have to use the other equation that convert wavelength to frequency.

4 0

2 years ago

At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?

rjkz [21]

E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. Relative rates of effusion is related to the molecular mass.
a) M(N₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, CO and N₂ have iexact molecular masses and will effuse at nearly identical rates.

8 0

2 years ago