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2 years ago

create visual representations that show the interactions between the particles in both samples during vaporization

1 answer:

7 0

Given what we know, we can confirm that despite not being able to provide a visual representation, if you were to create one, it would show the atoms in the substance moving with <u>more and more </u>energy over time until vaporization occurred.

<h3>What is vaporization?</h3>

Vaporization is the changing of a liquid into a gas.
This is known as a phase change.
This happens when the atoms receive enough heat energy.
The heat energy provides the atoms with kinetic energy and causes them to move faster over time.
When the kinetic energy is enough to rupture the bonds that hold a liquid together, it becomes a gas.

Therefore, given that vaporization is when atoms within a substance gain so much kinetic energy that they are able to rupture the bonds that hold them relatively close together and change into a gas, we can confirm that a visual representation would have to be a diagram showing the increased movement of atoms over time.

To learn more about vaporization visit:

brainly.com/question/11782435?referrer=searchResults

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Which of the following best describes AgCl

vagabundo [1.1K]

Answer: Where are the answers?

Explanation:

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2 years ago

Calculate the pOH of an aqueous solution of .0.073 M LiOH

Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

In summary, the pOH of the aqueous solution is 1.14

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7 0

2 years ago

How many atoms are in a sample of 175 grams of sodium (Na)? The answer needs to be <br> a x 10^b

ValentinkaMS [17]

Atomic mass Sodium ( Na ) = 22.98 u.m.a

22.98 g ----------------- 6.02x10²³ atoms
175 g ------------------- ?? atoms

175 x ( 6.02x10²³) / 22.98 =

4.58x10²⁴ atoms of Na

hope this helps!

4 0

2 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

2 years ago

In which of the following processes will delta S be negative?<br><br> Select one from above

Alona [7]

Answer:

CO2 (s) -->Co2 (g) will be the answer

3 0

2 years ago