Answer:
The empirical formula of the compound is =
The name of the compound is potassium bromate.
Explanation:
Mass of potassium = 4.628 g
Moles of potassium =
Mass of bromine = 9.457 g
Moles of bromine =
Mass of oxygen = 5.681 g
Moles of oxygen =
For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:
Potassium :
Bromine;
Oxygen ;
The empirical formula of the compound is =
The name of the compound is potassium bromate.
Answer:
Arderea de combustibili fosili, activități agricole, eșapament din fabrici și industrii, operațiuni miniere și poluarea aerului interior
Answer:
c2h4o2
Explanation:
I am using my cell. This could take a bit
The Empical formula has a mass of
C 12
2H 2
O 16
total = 30
The molecular mass is given as 60 which is 2 times the empirical mass. Therefore multiply each element by 2 in the empirical formula.
You get C2H4O2
Answer:
<u>It increases by a factor of four</u>
Explanation:
Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.
pV = K.......(1)
pV = constant
Charles law : The volume of the gas is directly proportional to temperature at constant pressure.
V = KT
or V/T = K = constant ....(2)
Applying equation (1) and (2)
According to question ,
T2 = 4 (T1)
V2 = V1
Put the value of T2 and V2 , The P2 can be calculated,
V1 and V1 cancel each other
T1 and T1 cancel each other
We get,
or
P2 = 4 P1
So pressure increased by the factor of four