The expected length of code for one encoded symbol is
where is the probability of picking the letter , and is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length , we would then expect .
By definition of variance, we have
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get .
The answer would be D) because its true and the difference is -0.2.
Answer:
Radius
Step-by-step explanation:
I know the answer
Answer: Scale factor of -1/2
Step-by-step explanation:
B=A*(-2)
A=B/(-2)
A=-(B/2)
A=B*(-1/2)
Scale factor of -1/2