Consider the equation of a circle x^2-2x+y^2-4y-4=0. If the line 2x-y+a=0 is its diameter. Then find the value of a.
1 answer:
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Answer: B) increasing for x < -4/3 and x > 4/3
decreasing for -4/3 < x < 4/3
<u>Step-by-step explanation:</u>
Graph the equation and follow the curve from left to right. If you are going up, it is increasing. If you are going down, it is decreasing.
Refer to the image below. Red is increasing. Blue is decreasing.
The vertices are at: x = -4/3 and x = 4/3
Answer:
40
Step-by-step explanation:
The data is
21,24,25,28,29,35,37,43,44
To find the third quartile we have to arrange the data in increasing order
so the data in increasing order is
21,24,25,28,29,35,37,43,44
total number of values = 9
Median value = (n + 1 )/ 2
=(9+1)/2
=5th value
so the median is 29
Lower half of the data is the values before the median and upper half of the data is values after the median
so lower half = {21,24,25,28}
Upper half = {35,37,43,44}
so to find the third quartile we will use the upper half of the values
Third quartile means that the median of the values of upper half of the data
As the total No of value in upper half is 4 which is an even no
we will take the middle values of the upper half and take their mean
so
Third Quartile =
=
=40
so the value of third quartile is 40