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1 year ago

Please help ;-; Solve for the simultaneous equation…. 5x+y=17 X+y=3

Mathematics

1 answer:

Svetach [21]1 year ago

4 0

Given Equation:-

5x+y=17 . . . . . . . . 1
x+y=3 . . . . . . . . . . 2

To find :

value of x
value of y

Solution :

Let's start with equation 2:-

x + y = 3

y = 3 - x

Put the value of y in Equation 1

5x+y=17
5x + (3 - x) = 17
5x - x + 3 = 17
4x + 3 = 17
4x = 17 - 3
4x = 14
x = 14/4
x = 7/2
x = 3.5

Now Let's find value of y:

put the value of x in equation 2:

y = 3 - x

y = 3 - 3.5

y = 0.5

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What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y

Korolek [52]

Answer:

$\displaystyle \boxed{y = -1\frac{1}{3}x + 22}$

Step-by-step explanation:

Parallel Equations have SIMILAR RATE OF CHANGES [SLOPES], so keep $\displaystyle -\frac{4}{3}$ as is and do this:

14 = −4⁄3[6] + b

14 = −8 + b

+ 8 + 8

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$\displaystyle 22 = b \\ \\ y = -1\frac{1}{3}x + 22$

I am joyous to assist you at any time.

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2 years ago

Can someone please answer and EXPLAIN ILL MARK BRAINLIEST

12345 [234]

Answer:

adjust city gallons to 3 gallons and freeway to 7 gallons

make your line in the chart:

3 | 10-3 = 7 | 3(25) = 75 | 7(40) = 280 | 75 =280 =355 | 355 | yes

Step-by-step explanation:

x = city gallons

y = freeway gallons

x+y = 10 then y = 10-x

25x+40y = 355

substitute for y

25x+40(10-x) = 355

25x+400-40x = 355

-15x+400 = 355

subtract 400 from each side

-15x = -45

divide both sides by -15

-15x/-15 = -45/-15

x = 3 gallons

y = 7 gallons

7 0

2 years ago

Read 2 more answers

Pyramid A has height 5 1/2, and Pyramid B has height 2 3/4. A and B are similar. What is the ratio of their:

N76 [4]

Answer:

Lateral areas have ratio of 4:1

Volumes have ratio of 8:1

Step-by-step explanation:

There is a rule in 3D geometry that when two solids are similar, and their edges are in the ratio of $a:b$ , the ratio of any surface area type measure is always $a^2:b^2$ this includes the lateral area, which is just a surface area minus the base, which is not important for this problem. The ratio of volumes of those similar solids is in the ratio of $a^3:b^3\\$ .

Now, to solve this, we need to find the ratio of any corresponding length of these similar pyramids. We have both the heights, so if we form a ratio of $\frac{5\frac{1}{2} }{2\frac{3}{4} }$ which if you simplify it, it is $\frac{5.5}{2.75}$ , which is $2$ . The ratio of the heights are $2:1$ .

Now we can apply those rules to this ratio, the ratio of lateral areas would then be $2^2:1^2$ , which is $4:1$ . the ratio of volumes would be $2^3:1^3$ , which is $8:1$