The quadratic equation that would model this scenario is
Let us take the side of the square = x
Area of the square = x²
Length of the rectangular garden = 2x
Width of the rectangular garden = x-16
So, the area of the new vegetable garden = length*width
Area of the new or rectangular vegetable garden = 2x(x-16)
<h3>What is a quadratic equation?</h3>
The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by coefficient non-zero.
Since it is given that
Area of square garden = area of the rectangular garden
Thus, the quadratic equation that would model this scenario is
To get more about quadratic equations refer to:
brainly.com/question/1214333
Answer:
$28.50
Step-by-step explanation:
The type of model that best fits the given situation is; A linear equation Model
<h3>What is the model of the equation?</h3>
Right inside the local reservoir we will have an initial amount of water A.
Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.
Thus, after t hours, the amount of water in the reservoir is expressed as:
W = A - 500gal * t
This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.
The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t
t = A/500 hours
Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }
Read more about Equation model at; brainly.com/question/25896797
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The original volume equation looks like this: V = 1/3 * h * (x^2)
After the side is reduced by 0.002, the new volume would look like V1 = 1/3 * h
* (x-0.002) ^ 2
Then we have:
V-V1 = 1/3*h*(x^2) - 1/3*h*(x – 0.002) ^2
= 1/3 * h *(x^2 - (x – 0.002) ^2)
= 1/3 * h * (0.004x - 0.00004)
The rate of decreasing is computed by:
(V-V1)/V * 100% = [1/3 * h *(0.004x - 0.00004)] / [1/3 * h * (x ^ 2)] *
100% this would be equal to (0.004x - 0.00004) / (x^2) * 100%
So replace x by 200, you’ll get:
(0.004(200) - 0.00004) / (200^2) * 100%
= 0.001999% is the rate of decreasing.
10/16, u just double 5/8 because 16 is double of 8.