We know that this is a parabola, as the equation is denoted by the x^2 term.
We can see that the symmetry is seen at the point -0.5, therefore making the axis of symmetry the vertical line -0.5.
The vertex is found in quadrant three. In other words, it will shift by a negative value both horizontally and vertically. The vertex is therefore (-0.5, -0.5).
We can verify this in the equations by using the formula (-b/2a) to find the vertex. The only quadratic equation that satisfies this is -2x^2 + 2x -1.
To sum it up, the answers are:
-2x^2 + 2x - 1.
AoS: x = -0.5
Vertex: (-0.5, -0.5).
Answer:
∠GJK is 22°
Step-by-step explanation:
Because the shape is a rectangle we know that GH is parallel to JI
This means that because of the alternate angle rule we know that
5x+8 = 7x-16
Then we solve for x
5x+8-5x = 7x-16-5x
8+16=2x-16+16
=
x=16
So this means that ∠HJI is 68°
Because the shape is a rectangle we know that ∠GJI is a right angle
This means that ∠GJK is 90-∠HJI because of the angles on a right angle rule
90-68 =22
∴∠GJK is 22°
r = -3/4p - 18/5
(or you could put 3.6 or 3 3/5 instead of 18/5)
2 - 3/4p = 5/6r + 5
-5 -5
-3 - 3/4p = 5/6r
/(5/6) /(5/6)
-18/5 - 3/4p = r
-3/4p - 18/5 = r