Answer:
c = 8.14 million×(0.9166)^t
4.83 million
Step-by-step explanation:
Data:
t = y - 2007
c₀ = 8.14 million
c₃ = 23 % less than c₁
Part 1. Calculate c₃
c₃ = c₀(1 - 0.23) = 0.77c₀
Part 2. Calculate r
c₃ = c₀r^t
0.77c₀ = c₀r³
0.77 = r³ Divided each side by c₀
r = 0.9166 Took the cube root of each side
The explicit decay model is c = 8.14 million×(0.9166)^t
Part 3. Prediction
t = 2013 - 2007 = 6
c = c₀r^t = 8.14 million×(0.9166)⁶ = 8.14 million × 0.5929 = 4.83 million
The model predicts that there will be 4.83 million cars for sale in 2013.
Answer:
Step-by-step explanation:
Domain : Set of all possible input values (x-values) on a graph
Codomain : Set of all possible out values for the input values (y-values) on the graph
Range : Actual output values for the input values (x-values) given on the graph.
Therefore, for the given graph,
Domain : (-∞, ∞)
Codomain : (-∞, 2]
Range : (-∞, 2]
From the given graph every input value there is a image or output value.
Therefore, the given function is onto.
The definition of a line segment is a line that will never end
Answer:
The answer is 5 5/8.
The correct answer is not in the options
He actually borrowed P=21349-3000=18349 (present value)
Assume the monthly interest is i.
then future value due to loan:
F1=P(1+i)^n=18349(1+i)^(5*12)=18349(1+i)^60
future value from monthly payment of A=352
F2=A((1+i)^n-1)/i=352((1+i)^60-1)/i
Since F1=F2 for the same loan, we have
18349(1+i)^60=352((1+i)^60-1)/i
Simplify notation by defining R=1+i, then
18349(R^60)-352(R^60-1)/(R-1)=0
Simplify further by multiplication by (R-1)
f(R)=18349*R^60*(R-1)-352(R^60-1)=0
Solve for R by trial and error, or by iteration to get R=1.004732
The APR is therefore
12*(1.004732-1)=0.056784, or 5.678% approx.
