The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Ok so we are using the Pythagorean theorem so were gonna do A^2 + B^2 = C^2
It don't say which leg we have so you can use either a or b.
Which would get us 14^2 + B^2 = 50^2
14*14 =196 , 50 *50 =2500
Then we have to subtract the two.
So 2500 - 196 = 2,304
Then you take the take the square root of that answer and you have your other leg.
The square root of 2,304 is 48
So the missing leg = 48
Answer:
27
Step-by-step explanation:
Here's the complete question:
Write the word sentence as an equation. Then solve the equation. A number k increased by 7 is 34.
An increase in k simply means that there's an addition. This will be:
k + 7 = 34
k = 34 - 7
k = 27
Therefore, the value of k is 27
Step-by-step explanation:
Answer:
Step-by-step explanation:
first term = a = 3
common ratio = 2nd term ÷ first term
= 12 ÷ 3
r = 4
