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2 years ago

7

3/4, 4/5, 7/8, 9/11, 5/6can they be simplified? give your reasons below.

2 answers:

Bad White [126]2 years ago

4 0

They cannot be simplified

zlopas [31]2 years ago

4 0

Answer:

No, none of these can be simplified

Step-by-step explanation:

Each one of these factions have a prime number in it, so therefore, you cannot simplify any of them. Prime numbers are numbers that only have 2 factors, one and itself. So, you can't simplify any of them.

Here's why:

If you take 3/4, you can't simplify because 3 is prime. 4 is NOT prime, but to reduce, you have to be able to find a GCF, or a greatest common factor.

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2 years ago

What is the solution to the system of equations? {x+2y=10y=12x+3

Marianna [84]

The solution to given system of equations are $(x,y) = (\frac{4}{25} , \frac{123}{25})$

<em><u>Solution:</u></em>

Given that we have to find solution to the system of equations

<em><u>Given equations are:</u></em>

x + 2y = 10 ------ eqn 1

y = 12x + 3 ------ eqn 2

We can solve the above equations by substitution method

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2(12x + 3) = 10

x + 24x + 6 = 10

25x = 10 - 6

25x = 4

$x = \frac{4}{25}$

<em><u>Substitute the above value of x in eqn 2</u></em>

$y = 12(\frac{4}{25}) + 3\\\\y = \frac{48}{25} + 3\\\\y = \frac{48+75}{25}\\\\y = \frac{123}{25}$

Thus the solution to given system of equations are $(x,y) = (\frac{4}{25} , \frac{123}{25})$

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2 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

2 years ago