Answer:
P( top two horses are predicted incorrectly in incorrect order)
= 
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in 
= 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
= 
=
Answer:
x=−2 or x=4
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
x2−2x−3=5
Step 2: Subtract 5 from both sides.
x2−2x−3−5=5−5
x2−2x−8=0
Step 3: Factor left side of equation.
(x+2)(x−4)=0
Step 4: Set factors equal to 0.
x+2=0 or x−4=0
x=−2 or x=4
Answer: 6
Step-by-step explanation: 36 divided by 6 equals 6
48 divided by8 is 6
common factor is 6
We have to add 3 2/3 + 2 2/3 using fraction strips. 3 2/3 and 2 2/3 are the mixed numbers. The mixed numbers consists of a whole number and a fraction. If we want to add those numbers we shoukld change them into improper fractions: 3 2/3 = ( 3 * 3 + 2 ) / 3 = 11 / 3; 2 2/3 = ( 2 * 3 + 2 ) / 2 = 8 / 3. Finally: 11 / 3 + 8 / 3 = ( 11 + 8 ) / 3 = 20 / 3 = 6 2/3. Answer: You reneme it turning them into improper fractions<span>. </span>
The answer is the last one
