Formula:
A(t)=P(1+(r/n))^)nt)
A(4)=2500(1+(0.04/4))^(4*4)
A(4) = 2500(1.01)^16
A(4) = 2500*1.1726
<span>A(4) = $2931.45</span>
Answer:
(-4,-1)
Step-by-step explanation:
Assuming the graph is the one shown in the attachment.
The forward sloping line has a slope of 1 and a y-intercept of 3.
The equation of this line is y=x+3
The horizontal line has a slope of 0 and y-intercept of -1.
It's equation is y=-1
The two lines intersect at (-4,-1)
Answer:
16/52, or 4/13.
Step-by-step explanation:
First, since we know that the question is asking for the probability of a club <u>or</u> a jack, we know that we have to add the two probabilities. The first probability is that of picking a club, which is 13/52. The probability of picking a jack (be sure not to overlap; don't double count the jack of clubs) is 3/52. Adding these two gives us 13/52+3/52=16/52, which simplifies to 4/13.
To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.
Let's plug it into the first equation first:
-2(3) - 4(-2) might = 2
-6 + 8 = 2
The first equation is true.
Now, we need to check the second equation:
3(3) + 4(-2) might =8
9 - 8 does not = 8
Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.
Hope this helps!