Explanation:
d = Diameter of wheel = 27 cm
r = Radius =
m = Mass of wheel = 800 g
= Initial angular velocity =
Equation of rotational motion
Moment of inertia is given by
Torque is given by
The torque the friction exerts is -0.0037406448 Nm
For more information on torque and moment of inertia refer
Answer:
W = 8.92 10² kJ
Explanation:
For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law
F = m a
a = F / m
a = 20 103/1400
a = 14.29 m/s²
With kinematics we can find the distance traveled
² = v₀² + 2 a x
x = ( ²-v₀²) / 2 a
x = (50² -35²) / 2 14.29
x = 1275 / 28.58
x = 44.61 m
Let's calculate the work
W = F.d
The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product
W = F d
W = 20 10³ 44.61
W = 8.92 10⁵ J
W = 8.92 10² kJ
Part a
The average speed = total distance traveled upon total time taken.
we know, distance =speed × time
Average speed =
insert the values:
= km/hr
= 46.43 km/hr
Hence, the average speed for the trip is 46.43 km/hr.
Part b
the total distance between two cities via this route would be the average speed times the total time taken = 46.43 km/hr × 2.9 hr = 134.65 km
(because 175 minutes = 2.9 hours)
Hence, the total distance between two cities via this route is 134.65 km.