Vitamin K and potassium are essential micronutrients the body needs to develop and function properly. The two share some things in common, but they’re not the same.
Each has a unique set of properties and purposes. Unlike vitamin K, potassium is not a vitamin. Rather, it’s a mineral.
On the periodic table, the chemical symbol for potassium is the letter K. Thus, people sometimes confuse potassium with vitamin K.
This article highlights some of the main similarities and differences between vitamin K and potassium.
The option which gives the correct mole ratios is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
<h3 /><h3>What is Mole ratio ?</h3>
It is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation
Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation
The balanced equation for given reaction is as follows ;
2H₂S + 3O₂ --> 2SO₂ + 2H₂O
Molar ratio can be determined by the coefficients of the compounds in the balanced reaction
Coefficient is the number in front of the chemical compound and they are as follows
- H₂S - 2
- O₂ - 3
- SO₂ - 2
- H₂O - 2
Therefore, correct option is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
Learn more about mole ratio here ;
https://brainly.in/question/32799056
#SPJ1
Answer:
c. Kay's rule
Explanation:
Kay's rule -
The rule is used to determine the pseudo reduced critical parameters of mixture , with the help of using the critical properties of the components of a given mixture .
The equation for Kay's rule is as follows ,
PV = Z RT
Where Z = The compressibility factor of the mixture .
Hence from the given options , the correct answer is Kay's rule .
It is (CI) bromine
because, <span>Halogen element, any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements are </span>fluorine (F)<span>, </span>chlorine (Cl), bromine (Br<span>), iodine (I), astatine (At), and tennessine (Ts).</span>