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1 year ago

HELP ASAP You are preparing to move into a new house. The walls of your room will measure 10 feet by 12 feet.

Mathematics

1 answer:

faltersainse [42]1 year ago

7 0

The Scale used on blueprint is 1 inches represents 4/3 feet

Scaling is the increase or decrease in size of a figure or object so as to create an image of that object.

Since on the blueprint, the walls measure 10 feet by 12 feet but on the blue print it measures 7.5 inches by 9 inches. Hence:

Scale used on blueprint is 7.5 inches = 10 feet or 9 inches = 12 feet

1 inches = 4/3 feet

The Scale used on blueprint is 1 inches represents 4/3 feet

Find out more at: brainly.com/question/20095188

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Don’t get this question , need some help thankssss

ss7ja [257]

Answer:

PQ = 37 Km

Step-by-step explanation:

let PQ = x , then

PR = x + 15 and QR = 3(x + 15) = 3x + 45

sum the parts and equate to 245

x + x + 15 + 3x + 45 = 245 , that is

5x + 60 = 245 ( subtract 60 from both sides )

5x = 185 ( divide both sides by 5 )

x = 37

then

PQ = x = 37 Km

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1 year ago

PLEASE HELP ASAP!!! I'LL GIVE BRAINLIEST TO WHO IS RIGHT!!!!

8090 [49]

6.9 I am pretty sure

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2 years ago

*ASAP*

In-s [12.5K]

If i can see it right, it would be A because it starts at 30, then rises as the number of rooms increases.

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2 years ago

What is the measure of

Lubov Fominskaja [6]

60.......................

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1 year ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

10 months ago